x2 + 2x + 1
= (x)2 + 2(x)(1) + (1)
= (x + 1)2
x2 – 2x + 1
= (x)2 – 2(x)(1) + (1)
= (x - 1)2
x2 + 4x + 4
= (x)2 + 2(x)(2) + (2)2
= (x + 2)2
x2 - 4x + 4
= (x)2 - 2(x)(2) + (2)2
=(x - 2)2
x2 + 8x + 16
= (x)2 + 2(x)(4) + (4)2
=(x + 4)2
9 dic 2007
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