(a+b)3 = a3 + 3a2b + 3ab2 = b3
x3 +6x2 + 12x + 8
= x3 +3(x2)(2)+ 3(2)2x + (2)3
= (x+2)3
-27x3 + 54x2y - 36xy2 + 8y3
= (-3x)3 + 3(-3x)2(2y) + 3(-3x)(2y)2 + (2y)3
= (-3x + 2y)3
-125x3 – 300x2y – 240xy2 - 64y2
= (-5x)3 + 3(-5x)2(-4y) + 3(-5x)(4y)2 + (4y)3
= (-3x + 2y)3
8x3 – 36x2 – 54x - 27
= (-2x)3 + 3(-2x)2(-3) + 3(-2x)(-3)2 + (-3)3
= (-2x - 3)3
64a3 + 48a + 12a + 1
= (4a)3 + 3(4a)2(1) + 3(4a)(1)2 + (4a)3
= (4a + 1)3
9 dic 2007
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